- 需求: 把一个 yaml 文件里边的一个节点的数据,分别转化成 tuple,最终用一个 list 来装 (用来给 pytest 做参数化)
# case.yaml
test_datas:
- "输入正确的用户名 1"
- username: test1
password: 123456
- expect_msg: success
- "输入错误的用户名"
- username: test2
password: 123456
- expect_msg: failed
- "输入正确的用户名 2"
- username: test3
password: 123456
- expect_msg: success
test_datas = [
("输入正确的用户名 1", {"username": "test1", "password": "123456"}, {"expect_msg": "success"}),
("输入错误的用户名", {"username": "test2", "password": "123456"}, {"expect_msg": "failed"}),
("输入正确的用户名 2", {"username": "test3", "password": "123456"}, {"expect_msg": "success"}),
]
- 然后我自己的读取 yaml 代码(就读了一个 yaml, 啥都没干,因为不会😥):
import yaml
def load_yaml(file_path):
with open(file_path, encoding='utf-8') as f:
data = yaml.safe_load(f)
return data # 这里实在不知道怎么处理了😭,求大佬帮忙
if __name__ == '__main__':
load_yaml("case.yaml")