没准有人是改内核呢

不明显，如果不能退换货，就当是阴影效果了呗

楼主买的三星的，换了 LG 的标

我觉得可以去二三四五线的事业性质各类研究所做计算机相关工作，比如数据库、高性能计算、机器学习什么的，如果这些地方 IT 业公司不够好的话。

@shm7 潮汐不错，专注+疗伤哈！纯音乐我也听不得，音乐有情绪，总感觉有声音和我说话似的。我只能听噪音😄

@gtanyin 弗洛伊德+酸葡萄定律了解一下？

@vcinex 对有些人确实有影响，我觉得可以放雷雨声的白噪音。但我集中精力做事时什么也听不得，这也是个弱点

楼主是否看过 python cookbook ？

If the values in the sequence are hashable, the problem can be easily solved using a set and a generator. For example:

def dedupe(items):
seen = set()
for item in items:
if item not in seen:
yield item seen.add(item)

Here is an example of how to use your function:
>>> a = [1, 5, 2, 1, 9, 1, 5, 10]
>>> list(dedupe(a))
[1, 5, 2, 9, 10]
>>>

This only works if the items in the sequence are hashable. If you are trying to eliminate duplicates in a sequence of unhashable types (such as dicts), you can make a slight change to this recipe, as follows:

def dedupe(items, key=None):
seen = set()
for item in items:
val = item if key is None else key(item)
if val not in seen:
yield item
seen.add(val)

Here, the purpose of the key argument is to specify a function that converts sequence items into a hashable type for the purposes of duplicate detection. Here ’ s how it works:
>>> a = [ {'x':1, 'y':2}, {'x':1, 'y':3}, {'x':1, 'y':2}, {'x':2, 'y':4}]
>>> list(dedupe(a, key=lambda d: (d['x'],d['y'])))
[{'x': 1, 'y': 2}, {'x': 1, 'y': 3}, {'x': 2, 'y': 4}]
>>> list(dedupe(a, key=lambda d: d['x']))
[{'x': 1, 'y': 2}, {'x': 2, 'y': 4}]
>>>
This latter solution also works nicely if you want to eliminate duplicates based on the value of a single field or attribute or a larger data structure.

@kkaka #9 自带的键盘很硬的有没有，习惯了还凑合，从红轴换过去感觉好累

@Zeonjl 有 200w 用来养一支好乐队都够了，唉

@Zeonjl 捉到一枚音响发烧友

@vvaix #4 是皇上穿越过来了

松本孝弘的“ 99 ”，你会回来感谢我的

做一个随机轮播中外双语对照文本的软件，可以是报刊资料或者外文名著等，放在手机 app 或者电脑屏保，随时学习外语