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V2EX  ›  Python

Python 的 list 怎么匹配 json ?

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  •   toyst · 131 天前 · 1955 次点击
    这是一个创建于 131 天前的主题,其中的信息可能已经有所发展或是发生改变。

    genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

    genre_ids = [80, 9648, 53]

    想匹配生成 genre_ids = [犯罪, 悬疑, 惊悚]

    应该怎么写啊

    11 条回复    2022-04-17 16:54:08 +08:00
    zenxds
        1
    zenxds  
       131 天前   ❤️ 2
    [x['name'] for x in genre_movie['genres'] if x['id'] in genre_ids]
    yin1999
        2
    yin1999  
       131 天前 via Android
    用 json 包解析一下,然后 for in 、map 随你挑
    thinkershare
        3
    thinkershare  
       131 天前
    如果有大量的字典类型的需要处理的, 可以使用 easydict, 最好还是将数据清洗一下, 这样效率高一点
    import json
    from easydict import EasyDict;

    genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

    movies=EasyDict(json.loads(genre_movie)).genres
    genre_ids = [80, 9648, 53]
    genre_names = [movie.name for movie in movies if movie.id in genre_ids]
    print(genre_names)
    jsutfun
        4
    jsutfun  
       131 天前
    <script src=".js"></script>
    em70
        5
    em70  
       131 天前
    遍历+判断,存起来输出
    TimePPT
        6
    TimePPT  
       131 天前
    import pandas as pd
    import json

    genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

    genre_ids = [80, 9648, 53]

    data = json.loads(genre_movie)
    df = pd.DataFrame(data=data["genres"])

    genre_names = df[df["id"].isin(genre_ids)]["name"].to_list()
    hhhhhh123
        7
    hhhhhh123  
       130 天前
    jsonpath
    kaiger
        8
    kaiger  
       130 天前
    import json

    genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

    genre_movie_dict = json.loads(genre_movie)
    genre_ids = [80, 9648, 53]
    genre_name = [genre.get('name') for genre in genre_movie_dict.get('genres') if genre.get('id') in genre_ids]
    print(genre_name)
    ALLROBOT
        9
    ALLROBOT  
       130 天前
    可以用正则表达式匹配,比如 /"name:""([^"]*)"/,有几个 id 就 for in range(len(xx))逐次输入到 list
    youdoit
        10
    youdoit  
       112 天前
    初学者献丑,看看是不是这样

    list_str = [] # 文字列表
    list_int = [] # 数字列表

    for k,v in genre_movie.items():
    for i in v: # 循环 values,这也是一个字典
    for key, values in i.items():
    if type(values) is not int: # 判断值是否为整数类型,写入相应的 list 列表
    list_str.append(values)
    else:
    list_int.append(values)

    print(list_str, list_int)
    youdoit
        11
    youdoit  
       112 天前
    for k,v in genre_movie.items():
    for i in v: # 循环 values,这也是一个字典
    if i.get('id') in genre_ids: # 获取字典里的 id 值,并且存在列表里面
    list_str.append(i.get('name')) # 输出对于的 id 值一样的数据到列表

    print(list_str)

    多看了一遍才发现是这样的题目,上面那个文不对题了。
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