python3 求助

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This topic created in 3950 days ago, the information mentioned may be changed or developed.

初学py3，

import urllib.request
def getHtml(url):
page=urllib.request.urlopen(url)
html=page.read()
return html
print getHtml('http://tieba.baidu.com')

运行提示出错，不知道错在哪儿，求教
print getHtml('http://tieba.baidu.com')
^
SyntaxError: invalid syntax

gethtml

syntax

4 replies • 2015-07-17 12:39:44 +08:00

bidu

Jul 17, 2015

print(getHtml('http://tieba.baidu.com'))试试？

Sylv

Jul 17, 2015 via iPhone

Python 3 要用 print(getHtml('http://tieba.baidu.com'))
print 不加括号是 Python 2 的语法

ecapsul

Jul 17, 2015

了解了，谢谢各位

jas0ndyq

Jul 17, 2015

doge